3. Program to get three numbers from user for integer variables a, b and c. If a is not zero, find out whether it is the common divisor of b and c.
Chapter 5:
Conditional Structures
Programming Exercise
Problem # 3:
Write a program to get three numbers from user for integer variables a, b and c. If a is not zero, find out whether it is the common divisor of b and c.
Solution:
#include<iostream>
#include<conio.h>
using namespace std;
int main ()
{
int a,b,c;
cout<<"Enter three integer numbers:";
cin>>a>>b>>c;
if(a!=0)
{
if(b%a==0&&c%a==0)
cout<<endl<<"a:"<<a<<" is a common divisor of b:"<<b<<"and c:"<<c;
else
cout<<endl<<"a:"<<a<<" is not a common divisor of b:"<<b<<"and c:"<<c;
}
else
cout<<"a is zero.";
return 0;
}
#include<conio.h>
using namespace std;
int main ()
{
int a,b,c;
cout<<"Enter three integer numbers:";
cin>>a>>b>>c;
if(a!=0)
{
if(b%a==0&&c%a==0)
cout<<endl<<"a:"<<a<<" is a common divisor of b:"<<b<<"and c:"<<c;
else
cout<<endl<<"a:"<<a<<" is not a common divisor of b:"<<b<<"and c:"<<c;
}
else
cout<<"a is zero.";
return 0;
}
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2. Program that accepts as input a salesperson's status in the character variable status. If status is 's' or 'S', the senior person's salary should be displayed; if status is 'j' or 'J', the junior person's salary should be displayed, otherwise display error message.
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