8. Program that repeatedly asks the user to enter two money amounts expressed in old-style British currency: pounds, shillings, and pence. The program should then add the two amounts and display the answer, again in pounds, shillings, and pence. Use a do loop that asks the user whether the program should be terminated.

Chapter 3: 

Loops and Decisions

Programming Exercise

Problem # 8:

Write a program that repeatedly asks the user to enter two money amounts expressed in old-style British currency: pounds, shillings, and pence. (See Exercises 10 and 12 in Chapter 2, “C++ Programming Basics.”) The program should then add the two amounts and display the answer, again in pounds, shillings, and pence. Use a do loop that asks the user whether the program should be terminated. Typical interaction might be
Enter first amount: £5.10.6
Enter second amount: £3.2.6
Total is £8.13.0
Do you wish to continue (y/n)?
To add the two amounts, you’ll need to carry 1 shilling when the pence value is greater than 11, and carry 1 pound when there are more than 19 shillings.

Solution:

#include<iostream>
#include<conio.h>
using namespace std;
int main()
{
    int pound1, shilling1, pence1, pound2, shilling2, pence2, poundSum, shillingSum, penceSum;
    char ch;
    do
    {
        cout<<"Enter first amount: \x9c"<<endl;
        cout<<"Enter Pound: ";
        cin>>pound1;
        cout<<"Enter Shilling: ";
        cin>>shilling1;
        cout<<"Enter Pence: ";
        cin>>pence1;
      
        cout<<"Enter second amount: \x9c"<<endl;
        cout<<"Enter Pound: ";
        cin>>pound2;
        cout<<"Enter Shilling: ";
        cin>>shilling2;
        cout<<"Enter Pence: ";
        cin>>pence2;
      
        poundSum=pound1+pound2;
        shillingSum=shilling1+shilling2;
        penceSum=pence1+pence2;
      
        if (penceSum >= 12){
            shillingSum = shillingSum + (penceSum/12);
            penceSum = penceSum%12;
        }
      
        if (shillingSum >= 20){
            poundSum = poundSum + (shillingSum/20);
            shillingSum = shillingSum%20;
        }
          
        cout<<"Total is :\x9c"<<poundSum<<"."<<shillingSum<<"."<<penceSum<<endl;
        cout<<"Do you wish to continue (y/n)?"<<endl;
        ch=getche();
    }while(ch=='y');
  
    return 0;
}

Let me know in the comment section if you have any question.

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